20x^2-136x+180=0

Solution for 20x^2-136x+180=0 equation:

20x^2-136x+180=0

a = 20; b = -136; c = +180;
Δ = b2-4ac
Δ = -1362-4·20·180
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-136)-64}{2*20}=\frac{72}{40}
=1+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-136)+64}{2*20}=\frac{200}{40}
=5
$